Transparent single crystals of PbSbO2Br (green), PbSbO2I, and PbBiO2Br (yellow) were obtained by solid state reactions of stoichionictric amounts of PbO, Pn(2)O(3) (Pn = Sb, Bi) and PnX(3) (X = Br, 1). The crystal structures were determined from single-crystal X-ray data. The title compounds crystallize tetragonally in the space group I4/mmm (No. 139): Lattice constants and refinement values are: PbSbO2Br: a = 3.9463(3), c = 12.849(1) angstrom, V = 200.10(3) angstrom(3), and Z = 2, R-1 = 0.0236, and wR(2) = 0.0513. PbSbO2I: a = 4.0074(3), c = 13.627(2) angstrom, V = 218.84(3) angstrom(3), and Z = 2, R-1 = 0.0244, and wR(2) = 0.0538. PbBiO2Br: a = 3.9818(2), c = 12.766(2) angstrom, V = 202.39(4) angstrom(3), and Z= 2, R-1 = 0.0276, and wR(2) = 0.0715. The compounds are isotypic and crystallize in the anti-ThCr2Si2 structure type with lead and Pn statistically disordered on one common position. In case of Pn = Sb a slight separation of the positions of the cations becomes obvious. Optical bandgaps were detennined by UV/Vis spectroscopy. They are 2.67 eV (PbSbO2Br), 2.48 eV (PbSbO2I), and 2.47 eV (PbBiO2Br).